3y^4-10y^2-48=

Solution for 3y^4-10y^2-48= equation:

Simplifying
3y4 + -10y2 + -48 = 0

Reorder the terms:
-48 + -10y2 + 3y4 = 0

Solving
-48 + -10y2 + 3y4 = 0

Solving for variable 'y'.

Factor a trinomial.
(-8 + -3y2)(6 + -1y2) = 0

Subproblem 1
Set the factor '(-8 + -3y2)' equal to zero and attempt to solve:

Simplifying
-8 + -3y2 = 0

Solving
-8 + -3y2 = 0

Move all terms containing y to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + -3y2 = 0 + 8

Combine like terms: -8 + 8 = 0
0 + -3y2 = 0 + 8
-3y2 = 0 + 8

Combine like terms: 0 + 8 = 8
-3y2 = 8

Divide each side by '-3'.
y2 = -2.666666667

Simplifying
y2 = -2.666666667

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.
Subproblem 2
Set the factor '(6 + -1y2)' equal to zero and attempt to solve:

Simplifying
6 + -1y2 = 0

Solving
6 + -1y2 = 0

Move all terms containing y to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -1y2 = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -1y2 = 0 + -6
-1y2 = 0 + -6

Combine like terms: 0 + -6 = -6
-1y2 = -6

Divide each side by '-1'.
y2 = 6

Simplifying
y2 = 6

Take the square root of each side:
y = {-2.449489743, 2.449489743}
Solution
y = {-2.449489743, 2.449489743}